The medohectillion is equal to \(10^{3\times 10^{603}+3}\).[1][2] It is defined using Sbiis Saibian's generalization of Jonathan Bowers' -illion system. It is the ducentillionth -illion.
Approximations[]
| Notation | Lower bound | Upper bound |
|---|---|---|
| Arrow notation | \(1000\uparrow(1+10\uparrow603)\) | |
| Down-arrow notation | \(1000\downarrow\downarrow202\) | \(87\downarrow\downarrow312\) |
| Steinhaus-Moser Notation | 250[3][3] | 251[3][3] |
| Copy notation | 2[2[604]] | 3[3[604]] |
| H* function | H(H(200)) | |
| Taro's multivariable Ackermann function | A(3,A(3,2003)) | A(3,A(3,2004)) |
| Pound-Star Notation | #*((1))*((235))*11 | #*((1))*((236))*11 |
| BEAF | {1000,1+{10,603}} | |
| Hyper-E notation | E(3+3E603) | |
| Bashicu matrix system | (0)(1)[44] | (0)(1)[45] |
| Hyperfactorial array notation | (294!)! | (295!)! |
| Fast-growing hierarchy | \(f_2(f_2(1995))\) | \(f_2(f_2(1996))\) |
| Hardy hierarchy | \(H_{\omega^22}(1995)\) | \(H_{\omega^22}(1996)\) |
| Slow-growing hierarchy | \(g_{\omega^{\omega^{\omega^26+3}3+3}}(10)\) | |