I tried to explain this page as clear as I could. Maybe I overdid it a little. :p wazzup Talk page 23:16, March 23, 2014 (UTC)
Okay...[]
1. n[m] = nn...nn/w m n's 2. n[a,b...y,z] = n[n[a,b...y,z-1],n[a,b...y,z-1]...n[a,b...y,z-1]] 3. n[a,b...y,1] = n[a,b...y]
a-b-meva = a[b] a-b-c-mevalka = a[b,c] a-b-c-d-mevena = a[b,c,d] a-b-c-d-e-mevmeva = a[b,c,d,e] a-b-c-d-e-f-mevmevalka = a[b,c,d,e,f] AarexTiaokhiao 21:57, March 27, 2014 (UTC)
- Well, okay. ☁ I want more clouds! ⛅ 05:24, March 28, 2014 (UTC)
- Okay! FB100Z • talk • contribs 05:26, March 28, 2014 (UTC)
Faster![]
n[a,b...y,z+1] = n[a,b...y,z+1](n) = n[n[a,b...y,z+1](n-1),n[a,b...y,z+1](n-1)...n[a,b...y,z+1](n-1),z], not n[a,b...y,z+1] = n[n[a,b...y,z],n[a,b...y,z]...n[a,b...y,z]]
n[a,b...y,z](1) = n[a,b...y,z,1] = n[a,b...y,z]
That make the notation faster. AarexTiaokhiao 01:53, March 30, 2014 (UTC)
Looking back, I got lost after I started reading the extension. Lol. wazzup Talk page 21:22, July 21, 2015 (UTC)
I'm liking this guy's notation, unique idea and pretty simple rules so far! As any googologist probably would, I now wonder what its current growth rate is. QuasarBooster (talk) 17:49, July 30, 2015 (UTC)
a[b] > a*10^b
a[[b]] > a*10^^b
a[[[b]]] > a*10^^^b
a[b,c] > a*10{c}b
a[b,c,d] - w+1
a[b,c,d,e] - w+2
a[b,c,d,e,f] - w+3
a[b#c] - w2
a[b##c] - w2+1
a[b###c] - w2+2
a[b##...##c] - w3 —Preceding unsigned comment added by 99.185.0.100 (talk • contribs) 14:35, August 2, 2015 (UTC)
An extension[]
- Add the plus signs between originally-defined #, ##, ###,...
- Then, let the new a[b##c]=a[b#+#+...(c #s)...+#+#b]
- a[b##+#c]=a[a[b##c]##a[b##c]], do same for ##+#+#, etc., and a[b##+##c]=a[b##+#+...(c #s)+#b]
- Then, define ###, ####,... similarly as new ## but replacing each ## with ###, ####,...
- a[b#^#c]=a[b####...(c times)...###b]
- a[b#^(#+n)c]=a[b(#^(#+n-1)c)b]
- a[b#^(#n)c]=a[b#^#*#^#*...(n-1 times)...#^#*#^#*(#^c)b]
- a[b#^##c]=a[b#^(#c)b].
- Continue with a[b#^#^#c], a[b#^#^#^#c]...
- a[b#^^#c]=a[b#^#^#^#^...(c times)...^#^#^#^#b].
- a[b#^^(#+1)c]=a[b(#^^#)^#^^#c]=a[b(#^^#)^(#^^c)b].
- Continue with pentation, hexation,...and use BEAF for defining farther.
- a[b{#,2,1,2}c]=a[b#{c}#b]
- a[b{#,3,1,2}c]=a[b#{#{c}#}#b]
- Continue with {#,4,1,2}, {#,5,1,2},...
- a[b{#,#,1,2}c]=a[b{#,c,1,2}b]
- Continue with {#,#+1,1,2}, {#,#+2,1,2},...,{#,#n,1,2},...,{#,#^n,1,2},... then expandal arrays as second argument,...
- a[b{#,#,2,2}c]=a[b{#,c,2,2}b]=a[b{#,{#,{#,...{#,{#,#,1,2},1,2}...,1,2},1,2},1,2}b] with c "#"s.
- Then continue with pentexpansion, hexexpansion,...
How fast does this extension grow? Is it even well-defined? 80.98.179.160 12:46, January 8, 2018 (UTC)
- What does a[b#^^(#+2)c] expand to? Rpakr (talk) 16:02, January 14, 2018 (UTC)
- This might reach \(f_{\Gamma_0}\). Rpakr (talk) 16:15, January 14, 2018 (UTC)
- Well, a[b#^^(#+2)c]=a[b#^^(#+1)^#^^(#+1)c]. 80.98.179.160 12:29, January 19, 2018 (UTC)
Extension to a[b##m][]
So a[b##m] is a real thing. What about a[b#c-m-2]? So a[b#c-m-2] is a[b###...(m #'s)...###c]. Then a[b#-m-3] is a[a[a[...(m times)...[a[b#c-b-2]#c-b-2]...(b times)...]#c-b-2]#c-b-2]. a[b#c-b#-m-2] = a[b#b-b###...(m times)...###c]. a[b#c-m-1-2] = a[b#c-b-b#c-b-b#c-...(m times)...-b#c]. a[b#c-m-1-1-2] = a[b#c-b-1-b#c-b-1-...(m times)...b#c] and so on! (please correct me if I had made a mistake) adumbperson adumbperson's talk